Double Integration Question originally asked by Jyqft: http://openstudy.com/updates/4ef626d7e4b01ad20b50b455
My Integration is a bit rusty, but I found this problem interesting... Could some show me step by step how you get to the answer? From the discussion I understood so far (hope I got it right): $$\int\limits\limits_1^2\int\limits\limits_0^{\frac{2-x}{2}} e^{y-y^2} dy dx$$ $$=\int\limits\limits_0^{1/2}\int\limits\limits_0^{2-2y} e^{y-y^2} dx dy$$

Question

Double Integration Question originally asked by Jyqft: http://openstudy.com/updates/4ef626d7e4b01ad20b50b455 
My Integration is a bit rusty, but I found this problem interesting... Could some show me step by step how you get to the answer? From the discussion I understood so far (hope I got it right): $$\int\limits\limits_1^2\int\limits\limits_0^{\frac{2-x}{2}} e^{y-y^2} dy dx$$ $$=\int\limits\limits_0^{1/2}\int\limits\limits_0^{2-2y} e^{y-y^2} dx dy$$

mr.math · Answer

The new limits are not correct. dx should be between 1 and 2-2y.