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If a knight starts out on square A1, can it land on every square exactly once and end on square H8?
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I definitely want to see how this is done. I have no clue.
So a knight lands on a white square, then a black square, then a white square, right? Well, the board has 64 squares. If it has to end on square H8, then it has to be a white square because A1 is a black square and 64 is an even number. However, H8 is a black square. So the answer is no.
Mathmate, the knight can definitely visit all of the squares. But in this case, the knight is starting on a specific square and ending on a specific square :)
Sorry, I didn't read the constraints! I agree with your answer.
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That is so very elegant.
Tracy, are you doing combinatorics?
wow
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