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Chemistry 9 Online
OpenStudy (anonymous):

Al + CaCl2 -> Metal + Salt

OpenStudy (anonymous):

Is it going to be: Ca + AlCl2 or No Reaction? This is a single displacement reaction.

OpenStudy (jfraser):

it should be AlCl3, but essentially you're correct

OpenStudy (anonymous):

oh, I believe it's AlCl3 'cause of the cross multiplication of charges right? Al +3 Cl-2? So, Al2Cl3 or just AlCl3?

OpenStudy (anonymous):

I meant Cl -1

OpenStudy (jfraser):

yes, cross the charges: Al+3 and Cl-1.

OpenStudy (anonymous):

But you know how you have to read an activity series cahrt for Singel displacement... Calcium is more reactive than Aluminum

OpenStudy (jfraser):

whether the reaction happens will depend on activities yes, but if it were to happen, the reaction would look like what you have above.

OpenStudy (anonymous):

ohh.. By the way, do you know the oxidation number for Cl4?

OpenStudy (anonymous):

Do you mean the chage of a cl4 molecule? that would be negitive 4

OpenStudy (anonymous):

ohhh.. i see, thank you!

OpenStudy (anonymous):

Any time keep those questions coming i will do my best to figure them out!

OpenStudy (anonymous):

I have this other question: Na + SnCl4 -> Metal + Salt. I put: 1 Na + 1 SnCl4 -> Sn + NaCl4 but since chlorine has a -4 charge and sodium has +1, should it be Na4Cl4? This is also a single displacement reaction.

OpenStudy (anonymous):

So you can rewrite this as \[4Na^+ +SnCl_4 \rightarrow Sn + 4 NaCl\] NaCl is table salt, I need to check on the charge of Sn

OpenStudy (anonymous):

Ok Sn can be +2 or +4 so we will just assume its plus four, you could also identify that by putting a roman numaral 4 in the subscript of the Sn atom

OpenStudy (anonymous):

ohh, alright. Thank you!!

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