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Mathematics 14 Online
OpenStudy (anonymous):

Given f(2x+1) = x^2 +2x +1. find f'(x).

OpenStudy (anonymous):

sorry. should be find f ' ( 2x +1 )

OpenStudy (turingtest):

ah, that makes it a little easier do you know the chain rule?

OpenStudy (anonymous):

I know chain rule

OpenStudy (turingtest):

ok, differentiate above using the chain rule on the left, and the power rule on the right. It won't be difficult to get f'(2x+1) after that.

OpenStudy (turingtest):

keira what do you get on the left after differentiating?

OpenStudy (anonymous):

I dont know. hehe

OpenStudy (anonymous):

I've tried, but I dont know how to do it

OpenStudy (turingtest):

The Chain rule is\[\frac{d}{dx}f(u)=f'(u)\frac{du}{dx}\]use\[u=2x+1\]and tell me what you get.

OpenStudy (anonymous):

2 ?

OpenStudy (turingtest):

well partly, but you have to keep the f'(u) part, that is important.

OpenStudy (anonymous):

I dont know hw to do the f'(u) part. :(

OpenStudy (turingtest):

just leave it as it is and sub in\[u=2x+1\]

OpenStudy (anonymous):

so the answer is x + 1 ?

OpenStudy (turingtest):

yes :)

OpenStudy (anonymous):

thanks a lot ! :)

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