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a vase is formed by rotating the portion of the curve y^2= x-6 between y=6 and y=-6
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about the y axis. Find the volume of the vase
Oops. Typo, hold on..
This is a disk method problem, which I assume you are familiar with. The radius of each disk is x = y^2 + 6 So the area of each disk is pi * (y^2+6)^2 = pi (y^4 + 72y^2 + 36) and the volume of each infinitesimal slice is pi (y^4 + 72y^2 + 36) dy Thus we want to evaluate the following integral: \[V = \pi \int_{-6}^{6} y^4 + 72 y^2 + 36 \space dy = 2\pi \int_0^6 y^4 + 72 y^2 + 36 \space dy\]
Oh damn it i did it again. that's not 72, it's 12 :)
thank you very much jemurray3!
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