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Use the quadratic formula to find the zeros of the function y = 2x2 + 3x + 6. Round to the nearest tenth if necessary. A. {-1.7, 2.3} B. {-2.4, 2.4} C. {-2.3, 0.8} D. no real solution
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No real solution. The quadratic formula would lead to: \[\Large \frac{{ - 3 \pm \sqrt { - 39} }}{4}\]So there are only complex roots.
complex roots
\[(-3\pm39i)/4\]
\[(-3 \pm j39)/4\]
So, the answer is D because the roots are imaginary (not real).
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well, actually the answer is a complex number, so it has a real part and an imaginary part
Sorry. I did not draw that level of distinction.
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