a line that passes through (1, 7), (10, 1)
find equation?
first we need the slope of the line any ideas how to find the slope?
i have no idea srry
y-y1/x-x1 = y2-y1/x2-x1 y-7/x-1 = 1-7/10-1 y-7/x-1 = -6/9 y-7 = -6x/9 +6/9 y=-6x/9 + 23/3
\[\text{ given two points} (x_1,y_1) \text{ and } (x_2,y_2) \text{ on a line }\] \[\text{ we can find the slope of that line and we will use m \to denote the slope of that line}\] \[m=\frac{y_2-y_1}{x_2-x_1}\]
y=-2/3x+ 23/3
ooh ok I think I get it
\[m=\frac{7-1}{1-10} \]
So the slope would be 6/9?
it doesn't matter if you chose your points the other way by the way almost
karate chopper simplified it 2/3
the opposite of 6/9
and it can be reduced like others are suggesting
the point to highlight is 1-10 in the denominator is -9, not positive...
happy boxing day, andy warhol
\[y=-\frac{2}{3}x+b\] so this is how much we know about the line now
but what is that b
that b is the y-intercept
thats the only thing left to find
you find b by pluggin' a point on the line (two points are given to you either point is fine to use)
\[y=-\frac{2}{3}x+b\] we know a point (1,7) where x is 1 and y is 7 so we plug these into the equation \[7=-\frac{2}{3}(1)+b\] and solve for b
\[7=\frac{-2}{3}+b\]
how do you solve this for b?
you plugin 1?
she plugged in the 1 already that's how you got the expression above so can you solve what is above for b ?
I don't know sorry.. plugin 2?
you don't need to plugin anything, just solve it
it's just linear equation, i believe you solved many of them
linear equations r fun
no i plugged in 1 for x and 7 for y since we have a point on the line called (1,7) 1 is in the x place 7 is in the y place so i just replaced them in the equation y=mx+b 7=m(1)+b 7=m+b so I want you to solve this for b by subtracting m on both sides 7-m=b b=7-m
yes^
ooh..
\[b=7-(\frac{-2}{3})=7+\frac{2}{3}\] so we found our equation of the line y=mx+b \[y=-\frac{2}{3}x+(7+\frac{2}{3})\] I will leave the simplifying to you
Ok
You don't need those parenthesis there i just wanted to be clear what I was saying b was
Ok, thank you
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