Eleanor has $1.60 in nickels and dimes. If there are 3 times as many quarters as nickles, how many of each type of coin does she have?
We just need help with this one question so we can figure out the rest of the sheet.
quarters?
Yes. Like in money.
Note: a "quarter" is a quarter dollar, worth $0.25 a "nickel" is a 5 cents coin, worth $0.05. Solving mentally: If there are three times as many quarters as nickels, then for every 3 quarters, we get a nickel for a sum of 3*0.25+0.05=$0.80. So $1.60 will have 2 sets of the above, or 6 quarters, and 2 nickels. Solving algebraically: Let N=number of nickels (each =0.05$) => 3N = number of quarters (each worth 0.25$). So 3N*0.25+N*0.05=1.60 0.80N = 1.60 N=1.60/0.80=2 (number of nickels) 3N = 3*2=6 = number of quarters). So answer: 6 quarters and 2 nickels for a total of $1.60.
Okay, thank you very much for explaining! ^^ This should help as a example for the rest of the sheet.
Good, just post if you have difficulties.
Okay, we will! Thanks again!
It says "Eleanor has $1.60 in nickels and dimes" though.
Oooh, I just read that there are "nickels and dimes", and later it says there are nickels and quarters. I think it's quarters, because dimes don't make an integer solution. Please check for typo.
It's quarters sorry, we just saw the typo! We're very sorry you guys! D:
No problem!
Solve the following for q, n and d:\[\left\{5n+10d=160,\frac{q}{n}=3\right\}\]\[\left\{n\to \frac{q}{3},d\to 16-\frac{q}{6}\right\} \]q has to be divisible by 6. Replace q by 6. Then:\[\{n\to 2,d\to 15\} \]5*2 + 10*15 = 160 ? 10 + 150 = 160 0.10 + 1.50 = 1.60
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