Question

A gas at 250K and 15atm has a molar volume 12% smaller than that calculated for the equation of state of an ideal gas. Hence calculate:

The compressibility factor (Z) for this temp and pressure The molar volume of the gas

Answer 1

a) By definition
\[ Z = \frac{V_{observed}}{V_{ideal \ gas \ law}} \]
Hence what is Z here?

b) Molar volume \( V_m \) is given by
\[ V_m = \frac{RT}{p} \]
where R is the ideal gas constant, T the temperature (in K of course) and p is the pressure. Hence, you now need to calculate.

Answer 2

(in part (b), just verify the units do what you want them to do; i.e., make sure that using pressure in atm is consistent with the R you are using.)

Answer 3

what is the volume for ideal gas?

Answer 4

You know V_observed is 12% smaller than V_ideal. So from that you can calculate Z.

Answer 5

how to get the compression fctor n molar volume for this q?