Find all points of discontinuity of f, where f is defined by :
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OpenStudy (mr.math):
Someone's studying!
OpenStudy (diyadiya):
\[\large \binom{\begin{cases}
|x|+3& \text{ if } x\leq -3 \\
-2x & \text{ if } -3<x<3 \\
6x+2 & \text{ if } x\geq 3
\end{cases}}{}\]
OpenStudy (mr.math):
Let's start with x=-3, okay?
OpenStudy (mr.math):
Can you tell me what's the limit as x approaches \(x^-\)?
OpenStudy (diyadiya):
ok
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OpenStudy (diyadiya):
isn't it \[3^-\]
OpenStudy (mr.math):
Yeah, I meant \(3^-\), what's the lmit?
OpenStudy (diyadiya):
|x|+3 so -x+3 & x+3 right?
OpenStudy (mr.math):
Note that \(|x|+3=-x+3\) for \(x\le -3\).
OpenStudy (mr.math):
She's a girl?
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OpenStudy (mr.math):
:P
OpenStudy (mr.math):
Anyways, what did you find for the limit?
OpenStudy (anonymous):
I gave her a medal.
OpenStudy (diyadiya):
why is it just -x+3 ? what about x+3 ?
@Fool I know!!
OpenStudy (mr.math):
Because x<=-3, right?
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OpenStudy (anonymous):
because of the constraints ..
OpenStudy (anonymous):
diya you are not thinking :/
OpenStudy (diyadiya):
oh ok
OpenStudy (anonymous):
That's not good thing ... Limit is a useful thing to understand ...
OpenStudy (mr.math):
I will help you with this one. FOCUS!
\[\lim_{x\to -3^-}f(x)=\lim_{x\to-3^-}|x|+3=\lim_{x\to-3^-}-x+3-=-(-3)+3=6.\]
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OpenStudy (mr.math):
Can you find the limit as x approaches \(-3^+\)?
OpenStudy (diyadiya):
wait wait
OpenStudy (mr.math):
\[\lim_{x\to -3^+}f(x)=\lim_{x\to -3^+}-2x=...\]
OpenStudy (diyadiya):
-2(-3)=6
OpenStudy (mr.math):
Good! Are they the same?
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OpenStudy (mr.math):
I mean the left and right limit as x ->3?
OpenStudy (diyadiya):
lol Yes
OpenStudy (mr.math):
What do you conclude then?
OpenStudy (diyadiya):
its continuos at -3
OpenStudy (mr.math):
What about f(-3)?
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OpenStudy (diyadiya):
f(-3)=-(-3)+3=6
OpenStudy (mr.math):
Now, you can say that f(x) is continuous at x=-3.
OpenStudy (mr.math):
Try to do the same with x=3, and write down what you get.
OpenStudy (diyadiya):
ok
OpenStudy (anonymous):
diya just when right hand limit and let hand limits are equal, we can only say that that the limit exist at that point.
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OpenStudy (mr.math):
Find left limit, right limit and the value of the function at that point. If they are all the same then it's continuous at that point.
OpenStudy (diyadiya):
yeah i know that :)
OpenStudy (mr.math):
Because you're smart! :P
OpenStudy (mr.math):
Why does Diya have two medals and I only have one?! ::P
OpenStudy (diyadiya):
ok wait i'll do the rest
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OpenStudy (diyadiya):
beacuse diya gives medals in the end!
OpenStudy (mr.math):
lol
OpenStudy (diyadiya):
\[\lim_{x \rightarrow 3^+}f(x)=\lim_{x \rightarrow 3^+}(6x+2)=20\]
\[\lim_{x \rightarrow 3^-}f(x)=\lim_{x \rightarrow 3^-}-2x=-6\]
\[f(3)=6(3)+2=20\]
\[LHL \neq RHL\]
So its discontionous at 3
Right or wrong ?
OpenStudy (mr.math):
Awesome!
OpenStudy (mr.math):
You deserve a medal NOW!
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OpenStudy (diyadiya):
Lol okay ofcourse You too!!
OpenStudy (diyadiya):
\[\huge THANK YOU \]
OpenStudy (diyadiya):
to both of you!
OpenStudy (anonymous):
analyze how this incident will affect the over all
automobile industry?
diya can u please translate it in urdu >
OpenStudy (anonymous):
nobody urdu here mam...
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