Question

Factor completely. Remember to look first for a common factor and to check by multiplying. If a polynomial is prime, state this. Going to try this and see what I come up with tell me if I am right
−81p^2 + 18pq − q^2

Answer 1

Let me try and help. Do you see any common factors?

Answer 2

9

Answer 3

9*2 and 9*9

Answer 4

The first two terms have 9, but not the last. How about factoring out the negative to obtain

−(81p^2 - 18pq + q^2)

Answer 5

9*2 and 9*9 is common to the first two terms, but not the third ...

Answer 6

okay 1 is a common factor

Answer 7

What are "good" numbers that multiply to make

81p^2

and

q^2

Answer 8

81*1 and 1*1

Answer 9

I like 1 * 1, but for 81, your answer is true, let's find another option? What else?

Answer 10

9*9

Answer 11

Good job! Therefore, we have

- (9p - 1)(9p - 1)

Answer 12

This is the trial and error method ...

Answer 13

okay

Answer 14

so all it does is help it to break down when factoring right

Answer 15

Yes, but we must break it down correctly, this time 81*1 did not work, but 9 * 9 did

Answer 16

so the complete break down would look like what then?

Answer 17

-81p^2 + 18pq - q^2= (-9p - 1)(9p - 1) so where does the "q" come in?

Answer 18

Oppps!

- (9p - q)(9p - q)

Answer 19

-(sorry*

Answer 20

okay now I got it