A particle moves along the x-axis so that at any time t0 its velocity is given by a(t)= ln(1+2^t) if the velocity of the particle is 2 at time t=1. then the velocity at time t=2 is? I originally got 1.609 as the answer. but apparently the correct answer is 3.346 where did i go wrong?

Question

A particle moves along the x-axis so that at any time t>0 its velocity is given by a(t)= ln(1+2^t) if the velocity of the particle is 2 at time t=1. then the velocity at time t=2  is?  I originally got 1.609 as the answer. but apparently the correct answer is 3.346 where did i go wrong?

liizzyliizz · Answer

its acceleration*  not velocity SORRY lol

liizzyliizz · Answer

acceleration is given by* :)

anonymous · Answer

ok- you need to integrate the function to get velocity

liizzyliizz · Answer

I started with  that, but I don't know where I made the mistake.

anonymous · Answer

to be honest,  the problem i've got is integrating the function

turingtest · Answer

is the formula you have for velocity?
or acceleration?

liizzyliizz · Answer

acceleration

turingtest · Answer

well jimmyrep is right, that is not an easy integral... http://www.wolframalpha.com/input/?i=int+ln%281%2B2%5Et%29

liizzyliizz · Answer

I'm still not quite sure where i went wrong lol. :[  im not quite sure how they got 3.346.

liizzyliizz · Answer

ahh ok nvm i saw your link. well. i certainly skipped a few steps and rules. *sigh*

liizzyliizz · Answer

there must be some rule or something that would make this problem easier. o.O

turingtest · Answer

there seems to be some inherent problem to me...
What level math is this supposed to be?
or physics?

liizzyliizz · Answer

AP calculus AB.