Question

3 + 8i/-3+4i

Answer 1

Multiply the numerator and denominator by the conjugate:

-3 - 4i

Does this help?

Answer 2

what is a conjugate

Answer 3

conjugate is found by changing the middle term. The conjugate of

5 + 3i

is

5 - 3i

Answer 4

so i divide 3+8i by -3-4i insted of its original

Answer 5

Multiply by -3 + 4i, both numerator and denominator

(3 + 8i)(-3 + 4i)
---------------
(-3+4i)(-3 + 4i)

Answer 6

5.85-2i is the final answer right

Answer 7

When multiplying I get

(3 + 8i)(-3 + 4i) -41 -12i
--------------- = -----------
(-3-4i)(-3 + 4i) 25

Answer 8

To make the denominator real we need to multiply and divide the given expression with conjugate of the denominator ie,(-3-4i)
\[(3+8i)(-3-4i)/(-3+4i)(-3-4i)\]
Now multiplying the numerator expressions
\[(-9-12i-24i-32i^2)/(9-32i^2)\]
Solving the above we get
\[(25-36i)/25\]
\[1-1.44i\] which is the answer

Answer 9

- so the processes are right but theses calcules are wrong
- first on denominator after you multiply by conjugate will get
(-3+4i)(-3-4i)=9-(-16)=25
- and on numerator (3+8i)(-3-4i)=-9-12i-24i-(-32)=9-36i+32=41-36i
- so than the answer will be

41 -36i
--------
25