Question

I need some serious help with standard form, Im really confused . Here's a problem ,
Write the equation y - 2 = 2(x - 3) in standard form.

Can someone help me to solve it so I can know how to solve other problems like it ?

Answer 1

Standard form is \[y = mx + b\]Let's use our algebra to solve this. First, add 2 to both sides. \[y = 2(x-3) + 2\]Then distribute the 2, and combine like terms. \[y = 2x - 6 + 2 = 2x - 4\]

Answer 2

Standard form is
ax+by=c
By solving above the equation we
y-2=2x-6
2x-y=6-2
2x-y=4 is the standard form equation
y=mx+c is not standard form but it is the slope-intercept form

Answer 3

@Atchyut , do those steps apply to all standard form problems like this one?

Answer 4

whoops! My form was slope-intercept. The same principles of algebra apply regardless of the required form.

Answer 5

standard form is
\[Ax+By=C\]

Answer 6

y - 2 = 2(x - 3)
The equation above is what is known as point slop form. There are three forms to an equation of a line and they are standard form, point slope form and slope intercept form.

Standard form = Ax + By = C
Point Slope = y - y1 = m(x - x1)
Slope Intercept = y = mx + b

In order to convert Point Slope or Slope Intercept from to standard form you have to get all the variables/terms to the left side and all the constants to the right. The C represents a constants.

Ok lets look at your equation which is in Point Slope form.

y - 2 = 2(x - 3)

First we need to get rid of the parenthesis, which is 2(x - 3), and we do this by distributing the 2
y - 2 = 2x -6

Now we move the variables/terms to the left side.

-2x + y - 2 = -6

Now we move our constants to the right side
-2x + y = -6 + 2

Now we do the math on the right side, which is -6 + 2,

-2x + y = -4

The above is in standard form now.

Answer 7

Yeah this is the actual procedure and u can follow DoodleTech gave very good info about basics of straight lines above