a^0=1,Is this true???

Question

turingtest · Answer

not true for 0^0, right?

anonymous · Answer

There you go moneybird its wrong for a=0

turingtest · Answer

that's rare that I'm right and moneybird is wrong...

anonymous · Answer

This question is just to know some of the basic thats it no offense sry

asnaseer · Answer

there is an article on this here: http://www.faqs.org/faqs/sci-math-faq/specialnumbers/0to0/

asnaseer · Answer

the main gist of it states:
"0^0 = 1 seems to be the most useful choice for 0^0 . This convention allows us to extend definitions in different areas of mathematics that otherwise would require treating 0 as a special case. Notice that 0^0 is a discontinuity of the function x^y .

This means that depending on the context where 0^0 occurs, you might wish to substitute it with 1, indeterminate or undefined/nonexistent."

anonymous · Answer

Yeah asnaseer 0^0 is equal to 0/0 (Use laws of indices (a/b)^m) which is an indeterminate

anonymous · Answer

yep it is

anonymous · Answer

provide that a is not = to 0