Question

Im stuck on this problem , Help please ?


Write the slope-intercept form of the equation parallel to y = 7x + 2, which passes through the point (1, -3).

Answer 1

When two lines are parallel their slopes are the same.

Use this formula, \[(y - y_1) = m(x-x_1)\] Then solve for y

Answer 2

I just used that formula and Im still not understanding.

Answer 3

What are you confused about?

Answer 4

Parallel lines have same slope then the required equation becomes y=7x+k k can be evaluated from the point given put x and y here

Answer 5

How do I incorporate that into this equation? I plugged everything into the formula (y-y1)=m(x-x1) and got y+3=7(x-1)

Answer 6

Now what do I do? :/

Answer 7

-3=7(1)+k implies k=-10
Required equation is y=7x-10 where slope is 7 and intercept is -10

Answer 8

Atchyut please help me with the question we started before please

Answer 9

Can u direct me to that question????

Answer 10

Now we have to use algebra to manipulate the equation into slope-intercept form. \[y +3 = 7(x-1)\]Now, let's subtract 3 from both sides.\[y = 7(x-1) - 3\]Now, let's distribute the 7. \[y = 7x - 7 - 3\]Now, let's combine like terms. \[y = 7x - 10\]

Answer 11

Oh that's simple , thankyou :) !