Andrew factored the expression20x^3-12x^2+8x as 4x(5x^2-12x^2+8x) . But when Melissa applied the distributive law and multiplied out4x(5x^2-12x^2+8x) , she got 20x^3-48x^3+32x^2; thus, Andrew’s solution does not appear to check. Why is that? Please help Andrew to understand this better. Explain your reasoning and correctly factor the original expression, if possible. If the expression is prime, so state
Andrew forgot to poll the 4 out of the rest of the numbers... he only changed the 20...
Hint: look at the second and third term inside the parenthesis
*pull
Because Andrew forgot to take the common from all the terms.
yeah he forgot the x too silly Andrew...
We should beat the ************** out of Andrew, he makes us boys look bad.
nope just you Fool lol
he makes me look smart lol
lol, you do such mistakes?
yeah I know I do but it also should be thought of a medal given to someone who tries to answer the problem
so from what I take of the problem Melissa was correct on her answer for the equation
btw what is a prime expression ?
"good answer" here is the correct factorization: 20x^3-12x^2+8x=4x(5x^2)-4x(3x)+4x(2)=4x(5x^2-3x+2)
4*12 is 48 4*5is 20 and 4*8 is 32
It looks like she just distributed his factorization to see if it matched the original. which it didn't.
don't forget the x's Sinz, he forgot to pull out the x from each term as well...
right but he also forgot to take his 4 away from the equation which is what Turning just stated as the true equation
Yes, those are the one/two mistakes he made, depending how you look at it.
Okay now I have a better understanding of the problem.
wow, we asked the same question.. are you in my class???
idk what class are you in and what school are you in?
i am taking college algebra at south university
Yeah me too
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