Question

solve

Answer 1

help!

Answer 2

\[\sqrt[3]{x+4}-2=13\]

Answer 3

You can add 2 to both sides of the equation to get:

Answer 4

i did that but what do i do with the index number

Answer 5

\[\sqrt[3]{x+4}=15\]

Answer 6

[x=15^{3}-4\]

Answer 7

raise to the 3 power.

Answer 8

raise what to the 3rd power

Answer 9

\[x=15^{3}-4\]

Answer 10

\[\sqrt{x+4}=(x+4)^{1/3}\]

Answer 11

A.x = 1
B. x = 3
C. x = 21
D. x = 98
these are the answers i have to choose from

Answer 12

To get rid of the \[\sqrt[3]{x+4}\]

Answer 13

raise it to the 3rd power.

Answer 14

I think you know how to do the rest.

Answer 15

so it would be x^3 +64=15

Answer 16

where did you get the 64?

Answer 17

i have no clue what to do im soo confused right now

Answer 18

like \[(a^{1/3})^3=a^{3/3}=a\]

Answer 19

I will write it.

Answer 20

okay