Question

Landing with a speed of 94.1 m/s, and traveling due south, a jet comes to rest in 929 m. Assuming the jet slows with constant acceleration, find the magnitude and direction of its acceleration.

Answer 1

Acceleration is the change in velocity over the change in time.\[(0m/s -94.1m/s)/t = acceleration (a)\]
From the preceding graph of speed with respect to time we can form the following equation:\[2(929m)/94.1m/s = t\] (t being time).

Combining the two equations, we have\[a = -(94.1m/s)^2/[2(929m)]\] which simplifies to \[a=[-(94.1)^2/1858]m/s^2\]Solving this, we find \[a \approx -4.7658m/s^2\]Your direction, of course, will be south.