How do you solve by substitution and graph with the problem: Eq. 1: y=1/4x + 2 and Eq. 2: y=-4x + 36?
You need to equal the right hand side of the first equation with the right hand side of the second equation.
You're told that\[y=\frac{1}{4}x+2\]and\[y=-4x+36.\]Could we then say that\[\frac{1}{4}x+2=-4x+36\]and solve for \(x\)?
And solve for x
And then you can find the x-intercept and y-intercept of each line.
I tried to solve for x, but i ended up with a really complicated fraction
make x = 0 and solve for y, to find the y-incercept
Wha did you get?
What if you multiply both sides by \(4\)?\[\frac{1}{4}x+2=-4x+36,\]\[x+8=-16x+144?\]Does that help with the fraction?
She multiply both sides of the equation by 4
multiplied
thank you so much!! Because i did that, i found out what x is. How would you solve by graphing?
You can follow this steps: - substract 8 from both sides of the equation. - add 16x to both sides of the equation. - divide by 17 both sides of the equation. And I think (if i'm not wrong) you get the value of x that satisfies the problem.
ahh.
Do you know how to graph a linear equation?
so you dont have to solve for y? you can solve for x to graph it?
Once you get the value of x, you can plug in to one of your equations and solve for y.
|dw:1325215086478:dw|
Did you get the value of y?
hold on, im still working the problem out
Did you get it?
to graph, do i have to start from 36 because the y intercept is 36 for y=-4x+36
yes if you let x = 0
so you have the coordinate (0,36)
You need the coordinates of another point on the line to graph it. You can get it with the x-intercept.
let y = 0, and solve for x.
so the x intercept would be 9 right?
Exactly!
So you have another coordinate (9,0)
You can do a line thar passes across those points.
and you can do the same for the other line.
pass, sorry
I'm not proud of my english =P
but your awsome at math :) if that makes you feel any better
haha thank you.
thank u :) this really helped alot
You're welcome =)
Join our real-time social learning platform and learn together with your friends!