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what is the domain of 1/ (X-square root of 2) ?
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Is it \(\large \frac{1}{x-\sqrt{2}}?\)
\[1 \over x - \sqrt{2}\]what value of x makes the denominator equal to zero?
yes and i have no idea eashmore
As eashmore said, you have to find the value that makes the denominator zero, that is \[x-\sqrt{2}=0 \implies x=\sqrt{2}.\]
Now, the domain is real numbers except that point at which the denominator is zero. So the domain is \((-\infty,\infty)-\{\sqrt{2}\}\).
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thanks man
After we find what values make the denominator equal to zero, we know that x can equal any other value because\[{1 \over 0}\]is undefined.
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