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Mathematics 19 Online
OpenStudy (anonymous):

Find the no. of arrangements of the letters in the word PENCILS if a) e preceeds i and b) there are three letters between e and i

OpenStudy (anonymous):

(a) I think 120, though I am not good at these types of questions

OpenStudy (anonymous):

abdul could you please show how you got your answ thx!

OpenStudy (anonymous):

I don't believe myself. Let joemath too post the answer, let's see if I am right.

OpenStudy (anonymous):

The second one is easier to explain. There are only 6 possibilities concerning the E and I. E___I__ I___E__ _E___I_ _I___E_ __E___I __I___E Pick one. Now we have 5 remaining letters to put in the other places. The number of ways we can do that is 5! = 120. So 120 ways for the 5 letters * 6 ways for the E and I gives 720 total combinations.

OpenStudy (anonymous):

For the E preceeding the I, again, looking at just E and I we get: EI_____ E_I____ E__I___ E___I__ E____I_ E_____I _EI____ _E_I___ ... so on and so forth. If you count them all, we get 21 ways (again, just looking at the E and I). Again, pick one of them. Now we look at the remaining letters. There are 5, and the total number of ways to arrange 5 things is 5! = 120. So 120* 21 = 2520

OpenStudy (anonymous):

Oh, I thought E just precedes I. Sorry

OpenStudy (anonymous):

Good explanation Joemath :)

OpenStudy (anonymous):

thank you abdul and joemath. however joemath may i ask whether there is a more efficient way of finding out there are 21ways other than drawing it out?

OpenStudy (anonymous):

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