Find the no. of arrangements of the letters in the word PENCILS if a) e preceeds i and b) there are three letters between e and i
(a) I think 120, though I am not good at these types of questions
abdul could you please show how you got your answ thx!
I don't believe myself. Let joemath too post the answer, let's see if I am right.
The second one is easier to explain. There are only 6 possibilities concerning the E and I. E___I__ I___E__ _E___I_ _I___E_ __E___I __I___E Pick one. Now we have 5 remaining letters to put in the other places. The number of ways we can do that is 5! = 120. So 120 ways for the 5 letters * 6 ways for the E and I gives 720 total combinations.
For the E preceeding the I, again, looking at just E and I we get: EI_____ E_I____ E__I___ E___I__ E____I_ E_____I _EI____ _E_I___ ... so on and so forth. If you count them all, we get 21 ways (again, just looking at the E and I). Again, pick one of them. Now we look at the remaining letters. There are 5, and the total number of ways to arrange 5 things is 5! = 120. So 120* 21 = 2520
Oh, I thought E just precedes I. Sorry
Good explanation Joemath :)
thank you abdul and joemath. however joemath may i ask whether there is a more efficient way of finding out there are 21ways other than drawing it out?
|dw:1325241633262:dw|
Join our real-time social learning platform and learn together with your friends!