I need an equation that represents the line that passes through the points (6, –3) and (–4, –9)? Thank in advance!
a line has form y=mx+b where m is the slope and b is the y-intercept these are the two things we need to find
do you know how to find the slope?
yes
so what is the slope here?
1,4?
\[m=\frac{ changey}{change x}=\frac{-3-(-9)}{6-(-4)}\]
thats not what i spelled lol
m=(change in y)/(change in x)
i see
\[m=\frac{-3+9}{6+4}=\frac{6}{10}=\frac{3}{5}\]
ok well that helps a bit
so now we can fill in one blank so we have \[y=\frac{3}{5}x+b\] so b is the only thing left to find
Use a point given to you in plug in that point to find b
like plug in x=6 and y=-3 (this is a point given to you) and now solve for b
i must go so maybe someone else can check your answer when you get it
-5 give or take?
well thanks...alot
\[-3=\frac{3}{5}(6)+b\]
\[-3-\frac{18}{5}=b\]
\[b=\frac{-3(5)}{5}-\frac{18}{5}=\frac{-15}{5}-\frac{18}{5}=\frac{-23}{5}\]
so i go now you have all the pieces of the puzzle now just put them in the right spot in you are done
ok cool thanks for writing it out rather than just throwin out the answer cuz it helps me learn
Another way of looking at it: If you have 2 points (6, –3) and (–4, –9), you can plug this in the equation y=mx+b to get 2 equations:\[-3=6m+b\]\[-9=-4m+b\] solve the simultaneous equations for m & b
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