Mathematics
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OpenStudy (anonymous):
put this equation 5x^2-4y^2-40x-16y=36 into the form of y^2/b^2-x^2/a^2=1 or x^2/a^2-y^2/b^2=1
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OpenStudy (anonymous):
note: i can't go on neither vyew or skype because of technical difficulites
OpenStudy (anonymous):
\[ 5x^2-4y^2-40x-16y=36 \]
OpenStudy (anonymous):
yes@nodata
OpenStudy (anonymous):
put all the math inside this \[ and
OpenStudy (anonymous):
5x^2-4y^2-40x-16y=36
5(x^2-8x+16)-4(y^2+16y+64)=36-64+(16*5)
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OpenStudy (anonymous):
\] this to make it look good
OpenStudy (anonymous):
i dont see the reason to make the equation "look good"
OpenStudy (anonymous):
its already ugly
OpenStudy (anonymous):
5(x-4)^2-4(y+8)^2=36-64+(16*5)
OpenStudy (anonymous):
Because we can understand it better.
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OpenStudy (anonymous):
ummm..idk@nodata
oh..so u completed the square?@big imran
OpenStudy (anonymous):
yes, that's what I did
OpenStudy (anonymous):
5(x-4)^2-4(y+8)^2=52
divide across by 52
OpenStudy (anonymous):
\[\frac{(x-x_0)^2}{a^2} + \frac{(y-y_0)^2}{b^2}=1 \]
OpenStudy (anonymous):
btw, I did something wrong arithmetically
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OpenStudy (anonymous):
wat?
OpenStudy (anonymous):
I think you can put it in that form if you complete the square
OpenStudy (anonymous):
lol..im kinda confused
OpenStudy (anonymous):
Sorry, It's a good a idea to complete the square.
OpenStudy (anonymous):
And imranmeah91 is working on that.
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OpenStudy (anonymous):
5x^2-4y^2-40x-16y=36
5(x^2-8x+16)-4(y^2+4y+4)=100
5(x-4)^2 -4(y+2)^2=100
OpenStudy (anonymous):
wait..where did the 100 com outta from?
OpenStudy (anonymous):
36+80-16=100
OpenStudy (anonymous):
i see where the 36 and 16 came outta..jus the 80
OpenStudy (anonymous):
\[\underline{5}(x^2-8x+\underline{16})-4(y^2+4y+4)=100\]
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OpenStudy (anonymous):
that's where 80 come from
OpenStudy (anonymous):
oh..lols im a slow learner..sry
OpenStudy (anonymous):
\[\frac{5(x-4)^2}{100}-4\frac{(y+2)^2}{100}=1\]
OpenStudy (anonymous):
is tht it? can we simplify anymore?
OpenStudy (anonymous):
\[\frac{(x-4)^2}{20}-\frac{(y+2)^2}{25}=1\]
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OpenStudy (anonymous):
kay...u simplify?
OpenStudy (anonymous):
since they want it in a^2 , b^2 form
\[\frac{(x-4)^2}{\sqrt{20}^2}-\frac{(y+2)^2}{5^2}=1\]
OpenStudy (anonymous):
and the x-4 and y+2 stay, or can they come outta the equation as well?
OpenStudy (anonymous):
no , they stay put
OpenStudy (anonymous):
okay! thank u soo much!!!!