How do you find the cube root of a number?
first find the prime factorization of the number
look for number closed by which has easy cube roots \[(28)^{1/3}\] \[(27)^{1/3}+(1/3)(27)^{-2/3}(1)\]=3.04
thanks! i think im basically done now... :)
How would that work if the desired number you wish to find the cube root is itself a prime number? Looks like logs would be a method.
No that's what i do... if i have options i multiply them
1. Calculator 2. Longhand method. Example: Find the cube root of 1000.57. Seperate into groups of three from the decimal dot: 1|000|.57 We do it like a division problem. the cube root of 1 is 1. subtract 1 from 1, leaving zero. then, find the largest x that fulfills 300A^2+30Ax+x^2 where A is the previous answer (1) 300+30x+x^2 in this case, it is zero. Write the 0 above the radical. Our answer now is 10. Now we continue to do this. note that .37 becomes 370. our remainder is 370. 300A^2+30Ax+x^2 30000+300x+x^2 again, find the largest x that can be in this case, zero again. Keep on going until the answer has the desired accuracy.
you dont look for easy numbers, how about the number is given?
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