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Physics 22 Online
OpenStudy (anonymous):

explain newtons law of cooling

OpenStudy (earthcitizen):

yh, that deals with Heat Transfer. radiation, Convection and Conduction

OpenStudy (anonymous):

yes can u explain me the derivation of formula

OpenStudy (earthcitizen):

Newton's law of cooling states, "For a body cooling in a draft (i.e., by forced convection), the rate of heat loss is proportional to the difference in temperatures between the body and its surroundings."

OpenStudy (anonymous):

twiddla plz?? by numerical too

OpenStudy (anonymous):

http://www.twiddla.com/711897

OpenStudy (anonymous):

?

OpenStudy (earthcitizen):

my twiddla is acting up

OpenStudy (anonymous):

means?

OpenStudy (earthcitizen):

http://www.twiddla.com/711897

OpenStudy (anonymous):

u r not showing der

OpenStudy (anonymous):

http://www.twiddla.com/711903

OpenStudy (anonymous):

u der

OpenStudy (earthcitizen):

http://www.twiddla.com/709728

OpenStudy (anonymous):

i m der

OpenStudy (earthcitizen):

\[Q _{conv}=hA(T _{s}-T _{\infty})\]

OpenStudy (anonymous):

can u explain me numerically how it comes

OpenStudy (anonymous):

bye tlk u after 4 hrs :)

OpenStudy (earthcitizen):

yh

OpenStudy (earthcitizen):

thnx!

OpenStudy (jamesj):

As EC suggests, Newton's law of cooling says that the rate of change of temperature of a body (e.g., a cup of tea) in a large environment (like sitting on the table in your kitchen) is proportional to the difference in temperature between the body and the environment. To put it in symbols, let T be the temperature of the coffee and \( T_r \) be the temperature of the room. The rate of change of temperature we write as \[ \frac{ \Delta T}{\Delta t} \] where little t is time. Newton's law of cooling says this is proportional to \( -(T - T_r) \). That is, there is some positive constant k such that \[ \frac{ \Delta T}{\Delta t} = -k(T - T_r) \] What that means is if the tea is a lot hotter than the room; e.g., \( T_r = 20 C \) and \( T = 80 C \), then it will cool quickly, at a rate of \[ \frac{ \Delta T}{\Delta t} = -k(T - T_r) = -k(80 - 20) = -80k \] But later on with the tea is cooler, say T = 40 C, then the tea will cool at a rate of \[ \frac{ \Delta T}{\Delta t} = -k(T - T_r) = -k(40 - 20) = -20k \] which is 1/4th as slow. Here's an example diagram showing how the temperature of the tea changes over time and converges on the temperature of the room: In the diagram the vertical axis is temperature in C; the horizontal axis is time in minutes. Hope that helps.

OpenStudy (anonymous):

can u tell me how dat formula came

OpenStudy (jamesj):

Yes, by doing an experiment. You can replicate the experiment. Take a cup of water at 80 C or whatever; put a thermometer in it; measure and record the temperature every 1 minute. Then draw a plot of temperature of the water vs. the change in temperature over 1 minute. That set of data points will be close to a straight line and the slope of the line is -k where k is the constant of proportionality.

OpenStudy (anonymous):

i need a derivation of dat formula actually..

OpenStudy (jamesj):

Starting from general thermodynamical principles you mean? If so, maybe this gives you what you need: http://physics.unipune.ernet.in/~phyed/23.1/23.1_teaching.pdf

OpenStudy (anonymous):

thanQ..

OpenStudy (anonymous):

i found tat we can even use newtons law in another way.... like if A- acceleration, Vi- initial velocity and Vo- is final velocity then we can write it as ; |dw:1325412524225:dw| by which we can write tat: A=V/T... sooo ..we can use it anyway

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