A child kicks a ball resting on a smooth floor in a room .the ball rebounds from one wall with reduced speed and moves to opp wall where it stops .draw position time graph and xplain

Question

turingtest · Answer

I'm guessing smooth floor means no friction.
Where is the ball initially kicked from? the other wall?
that can change things slightly.

aravindg · Answer

no friction

aravindg · Answer

from the floor

turingtest · Answer

So I guess the only time it slows down is when it hits the other wall.
Velocity will be the derivative (and therefor slope) of the graph. It will be one slope on the way to the first wall, on a smaller slope on the way back to the second.
I know the ball is kicked from the floor in the y-direction, but what x does it start at?

aravindg · Answer

any

turingtest · Answer

ok...
then we have an arbitrary starting point. I think we can call it x=a.
let the front wall be x=w and the back wall be x=0. on the way to the first wall we have|dw:1325353827503:dw|I wrote that it hits the wall at time t=t1.
what about the way back? it will go all the way to x=0, with a smaller slope (because it says it moves slower this in this direction). can you graph that bit?

anonymous · Answer

i think two things are responsible for it:-   1.) friction wd floor 2.) deaccleration effect caused by the wall( it depends upon wall moment.) and one more thing is 'velocity time' graph or 'energy time' graph is more important in this case than 'position time' graph.