Prove the identity: (1-sinx)(secx+tanx)=1 over secx P.s. Happy new years everyone!!! :)
happy new years
convert secx to 1/cosx convert 1/secx to cos x convert tanx to sinx/cosx then just multiply. You will wind up with 1-sin^2x in the numerator. Rewrite that as cos^2 and it's done.
sec is h/a tan is o/a sin is o/h
thank you sunsetlove...
sec is h/a tan is o/a sin is o/h ?
forget that, just listen to my post. can you do that? what do you get?
so, (1-sinx)(1 over cosx + sinx over cosx) and if I multiply..
yes... see what you get
ohh \[1-\sin ^{2} \theta \over \cos \theta \] !??
good and what is 1-sin^2x=??? (very important identity)
\[\cos ^{2}x\]
so the fraction becomes...?
gotcha! :) wooooo la la. Thanks ;)
cosx which is same as the right side :)
Nice job Hannah!
I have to say you are very helpful! :)
I try, thanks for listening :)
btw, did memorize all of these identities?
did u *
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