Solve each equation for 0le x < 2pi . 3cos ^{2}x -2cosx - 1 = 0 and the answer is 0, 1.9106, and 4.3726 I got the zero but how do I get the decimal numbers...
\[0\le x < 2\pi\]
is that ur anser
pardon me ?
the answer is 0, 1.9106, and 4.3726
u have the answer than why did u ask a question
I got 0. but I don't know how to get 1.9106 and 4,326
ow ok
can you factor your equation? what did you get?
show ur work please
haha sure wait a sec
factored. (cosx-1)(3cosx+1). so when cosx is 1 the solution for this is 0. but when cosx is -1 over 3.. I am supposed to get the decimal number answers but I don't know how.
Are you in radian mode?
\[(\cos(x)-1)(3\cos(x)+1)=0\] \[\cos(x)=1\implies x=0\] \[\cos(x)=-\frac{1}{3}\implies x=\cos^{-1}(-\frac{1}{3})\] then a calculator
then i get 1.9106...
yes i am in radian mode
yes thats importent i cep getting the rong answer till i put in the right mode
oh an since you are on the interval \[[0,2\pi]\] you should add \[\pi\] to the second answer
no sat she need to subtract her answer from 2pi
Well yes so you got 1.9106... right? what about the other value? As sat and I were talking about the cosine will have this value twice, just look at the unit circle...
I don't know if I am supposed to subract that number by 2 pi or plus the number by pi
so say this is where the cosine is -1/3:|dw:1325371641604:dw|can you find another spot that is also the same value of cosine?
oh plus 2 pi
another unit circle
well, 2pi-(this angle)|dw:1325371755653:dw|the same value here occurs at 2pi-x
actually 2 pi - 1.9106 ?
right, look at the circle to see why...
|dw:1325371831521:dw|
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