Question

plz do it

Answer 1

given a chemical reaction in turning methyl salicylate into salicylic acid using basic solution as shown in the file .
if we use methyl salicylate 3.80 gram to react with Sodium Hydroxide Solution at the concentration of 4 molar 20 mL after the reaction is completed, add Sulfuric acid solution at the concentration of 2 molar to precipitate salicylic acid
1)what is the volume of sulfuric acid that we need to add to fully parcipitate salicylic acid
2)if we got salicylic acid 2.76 gram. what is the percent yield of salicylic acid?

Answer 2

\[C_6H_4(OH)(COOH)+ CH_3OH \rightarrow C_6H_4(COOCH_3) + H_2O\]

Answer 3

Now we do a little stoichometry, MS= methyl salicylate, SA=salicylic acid

\[3.80 g MS(\frac{1 mole MS}{138.13 g MS})(\frac{1 mole SH}{1 mole MS})(\frac{135.15 g SH}{1 mole SH})=3.72g SH\]

Now we know the theoretical yeild is 3.72g of S Acid, but we want to find the percent yeild using the following formula

\[(\frac{theortical yeild-actual yeild}{theortical yeild})X100=percent yeild\]

\[(\frac{3.72g-2.76g}{3.72g})X100=25.8%\]

Answer 4

thx a lot

Answer 5

No problem hope that helped

Answer 6

How about 1) ?

Answer 7

So am i reading it right you want to nutrilize it with naoh then go back titrate it?

Answer 8

aha

Answer 9

Did you get it MrBank?

Answer 10

yes

Answer 11

ok

Answer 12

thx again zbay

Answer 13

Anytime

Answer 14

hey, the percent yield formula is supposed to be (actual yield (gram)/ theoretical yield (gram)) x 100