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OpenStudy (anonymous):
solve: lim(x->pie/2) sinx^(tanx)
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OpenStudy (diyadiya):
\[\lim_{x \rightarrow \frac{\pi}{2}} sinx^{tanx}=\sin({ \frac{\pi}{2}})^\tan \frac{\pi}{2}= 1\]
OpenStudy (anonymous):
i don't understand how you got 1 ans??
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