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Mathematics 8 Online
OpenStudy (anonymous):

my question is not answered. someone help!

OpenStudy (anonymous):

in a card game between mr.A and mr.B there are agreements below 1)two player have to take turns picking. one by one 2)mr.A will win if he get QUEEN card before mr.B 3)mr.B will win if he get KING card before mr.A find the way that mr.A will win and not taking cards more 2(2 is maximum)

OpenStudy (anonymous):

what does the last sentence mean?

OpenStudy (anonymous):

not taking cards more than 2 = two cards are maximun for picking

OpenStudy (anonymous):

Mr A will win if the following happens {Q} {not Q, not K, Q} {not Q, not K, not Q, not K, Q} etc

OpenStudy (anonymous):

if two cards are maximum for picking, then it is just {Q} {not Q, not K, Q}

OpenStudy (anonymous):

if the question is "what is the probability that Mr A wins?" then you need to specify whether the chosen cards are replaced in the deck or not

OpenStudy (anonymous):

hmmm maybe i did not read carefully. who wins if Mr. B gets a Queen before Mr A?

OpenStudy (anonymous):

I agree with satellite

OpenStudy (anonymous):

thanks, but i am not sure now i am right. i assumed it was "Mr A wins if he gets a Queen and Mr B wins if he draws a King" but it is not that clear, because it says "mr.A will win if he get QUEEN card before mr.B" so what happens if for example Mr A draws a not Queen and them Mr. B draws a Queen?

OpenStudy (anonymous):

need some clarification here i think

OpenStudy (anonymous):

Well I think if Mr.A draw only Queen - he's the winner. and if Mr.B draw only King - he wins my mistakes sorry ;P

OpenStudy (anonymous):

ok then my first answer is correct. two ways for mr A to win drawing no more that two cards 1) Q on first draw 2) not Q, mr B gets not K, Q

OpenStudy (anonymous):

yes but plz give me the total number of those methods

OpenStudy (anonymous):

what do you mean "total number"? there are two ways. do you mean the probability of each?

OpenStudy (anonymous):

probability the first card is a queen is \[\frac{4}{52}=\frac{1}{13}\]

OpenStudy (anonymous):

then if the card is replaced (this makes a difference) the probability of not Q, not K, Q is \[\frac{48}{52}\times \frac{48}{52}\times \frac{4}{52}\]

OpenStudy (anonymous):

add them up to get the probability that Mr A wins

OpenStudy (anonymous):

thx and sorry by the way. because i'm not learning math in english. as that i'll have problems in math explanation for a bit.

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