Question

Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth.

-2y^2-8y = -6

Answer 1

It is the same as:
2y^2 + 8y - 6 = 0
It is the same as:
y^2 + 4y - 3 = 0

Quadratic formula says (-b +/- SQRT(b^2-4ac))/2a

Answer 2

\[\frac{-b \pm \sqrt{b^2-4ac}}{2a}\]

Answer 3

So implementing my equation into the formula, what would it look like?

Answer 4

That formula applies to quadratic equations of the form:
ay^2 + by + c. Find a, b and c in the above equation I showed. Then, plug in!

Answer 5

And, from there, you will find your two y's?

Answer 6

I'll try it.

Answer 7

You got it! Sometimes you will only find one root.

Answer 8

For equations of the form (y+k)^2, there is only one root. As, b^2-4ac will be zero.

Answer 9

Well, the answer choices all have two different numbers, so I will just try it and see how it works. Gimme 1 sec. How about we both work it, so I can see if I am doing it correctly?

Answer 10

If that's alright with you.

Answer 11

I am here. I will await.

Answer 12

Okay. Thanks.

Answer 13

-4 +/- SQRT(4^2 - 4y3)/2y?

Answer 14

a = 1

Answer 15

c = -3

Answer 16

So, you should get:
(-4 +/- SQRT(16+12))/2
=> (-4 +/- SQRT(28))/2
=> -2 +/- SQRT(7)

Answer 17

ah