solve problem using the fundamental theorem of calculus: f'(x)=cos(x^3) and f(0)=2. Find f(1). Please and thank you :)
We need to find f given f' To do we need to integrate f'
are you sure its cos(x^3)
yup.. completely sure :)
so this is advanced calculus?
or complex analysis
I guess.. my teacher's kinda cruel xD..
i can't help you with this one. cos(x^3) is not an elementary integral
sorry
It says you can use a calculator though. Would that make a difference? :(
are you sure it isn't cos^3(x)?
nope, it definitely is not.
:(
the indefinate inate integral is here: http://www.wolframalpha.com/input/?i=integral%28cos%28x%5E3%29%29
idk if that helps
zed you got anything to say about this problem?
I think we need to use the Maclaurin series expansion of cos(x^3)
We would only be able to approximate the constant that way right?
yes that's correct.
It doesn't make sense. He just posted a cal 1 problem above.
Have you learned about Macluarin series?
No.... @.@
I think it was a mistake that this problem was given to you. You are talking about the fundamental thm of calculus with a extremely tough integral (one that is not elementary).
I think myininaya is right, this is quite difficult to do.
if it was cos^3(x) that would have been doable by cal 1 ways
alright, I'll leave it for last... If anything, I'll just complain to my professor xD.. Thank you guys very much
or maybe cal 2 whatever
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