A particle moves along the x-axis so that at any time t0, its acceleration is given by a(t)=ln(1+2^t). If the velocity of the particle is 2 at time t=1, then what is the velocity of the particle at time t=2?

Question

A particle moves along the x-axis so that at any time t>0, its acceleration is given by a(t)=ln(1+2^t). If the velocity of the particle is 2 at time t=1, then what is the velocity of the particle at time t=2?

anonymous · Answer

integrate a(t) with respect to t to get v(t) (don't forget the const.), use v(1) = 2 to get the const. and compute v(2). If I didn't miss something out, that should do it...

anonymous · Answer

also is that 2^t or maybe t^2?

anonymous · Answer

no it's 2^t

anonymous · Answer

which is why i dont know how to solve it :C

anonymous · Answer

hehe, I see... I'm sorry then, I don't know. You can try plug it in wolfram alpha, might help...

anonymous · Answer

I did and it gave me something incomprehensible. Thanks for trying though <3

anonymous · Answer

np