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OpenStudy (anonymous):
a trigonometry question#5
given
tan x/2=y
find cos x/(1+sinx) in y term
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OpenStudy (mertsj):
tan(x/2)= sinx/(1+cosx)
OpenStudy (mertsj):
Multiply numerator and denominator by (1-cosx)
OpenStudy (mertsj):
That will lead you to a good place.
OpenStudy (anonymous):
i'm not doing in that way. can you try and give me an anz
OpenStudy (anonymous):
where is "tan(x/2)= sinx/(1+cosx)" from?
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OpenStudy (mertsj):
It's a half angle formula.
myininaya (myininaya):
i got another way
myininaya (myininaya):
just a sec
OpenStudy (anonymous):
i think it can be written in several form
OpenStudy (anonymous):
let me give you guy choices
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myininaya (myininaya):
scanning...
myininaya (myininaya):
OpenStudy (anonymous):
a.\[1-y^2/(1+y)^2\]
b.\[1-y^2/1+y^2\]
c.\[y^2-1/y^2+1\]
d. \[y^2-1/(y+1)^2\]
myininaya (myininaya):
so we have
\[\frac{\frac{1-y^2}{y^2+1}}{1+\frac{2y}{y^2+1}} \cdot \frac{y^2+1}{y^2+1}=\frac{1-y^2}{y^2+1+2y}=\frac{1-y^2}{(y+1)^2}\]
myininaya (myininaya):
after simplification
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myininaya (myininaya):
I really couldn't get it the way mert was doing
i found this way perfect though
myininaya (myininaya):
can you real my pdf?
myininaya (myininaya):
read*
OpenStudy (anonymous):
yes same here thx
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