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Another one: Given that all roots of the equation \( x^5 − 10x^4 + ax^3 + bx^2 + cx − 32 = 0 \) are real and positive.Find \( a+b+c \)
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40 LOL
Explain.
from viete i got that x1*x2*x3*x4*x5=-32 so i just guess that 2 is one of the factor and i guess by (x-2)^5 and multiply it together and get the result \[x^5-10x^4+40x^3-80x^2+80x-32=0\] so a+b+c=40-80+80=40
could be a kind of stupid way to do lol
lol, yeah but you got the correct solution.
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cool lol you have a better way?
May be ;), but let see how others solve it
wow thats totally lucky.
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