Let \( f \) be a function in two variables defined for natural numbers and satisfying 1) \( f(x, x) = x \) 2)\( f(x, y) = f(y, x) \) 3)\( (x + y)f(x, y) = y.f (x, x + y) \) Then find the value of \( f(252, 90) \).
f=0 works but I suppose you wanted a non-trivial answer...
is it 19/5
sorry , half the way
i dont know but is it 5
The answer is not 5 or 19/5.
2520?
1260 is the answer. LCM ;)
yay! joemath
Slight variation, what would the answer be if the third rule was: \[3) f(x,y)=f(x,y-x)\]
sorry Professor Joemath
wait, miss type >.< it should be y+x in the second argument....now that i think about it lol
So third rule:\[f(x,y) = f(x,y+x)\]
GCD isn't ?
8?
yep :) these were interesting problems. Writing out proofs for the solutions were fun.
but foolformath's third rule makes it hard
for me
If you try it with smaller numbers its easier to see.
no really Ishaan, you just don't know (yet) how to tackle these kinds of problems :)
joe is professor ??
im not >.> akshay started calling me that lol. Im a lowly undergraduate.
lol cool man :D
btw joe what about \[ f(x,y)=f(x,y-x) \] ?
ah that was a mistype. although it would lead to the same solution, GCD.
yeah :D
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