can some please explain...
if the function g is defined as g(x) = (t squared - 3t-4) dt on the interval [-7,5], then g(x) has a local minimun at x=

Question

anonymous · Answer

you have to find the critical numbers, by obtaining the derivaitve and setting it to zero.  Then you have to test those numbers, as well as the end points

anonymous · Answer

take it this is 
$$g(x)=\int_{-7}^x t^2-3t-4 dt$$ right?

anonymous · Answer

yeah, ok so i have to test 3/2, -7, and 5?

anonymous · Answer

what lagrange said.
take the derivative, get 
$$g'(x)=x^2-3x-4$$ by FT of C
then set = 0 and solve

anonymous · Answer

yeah so is the derivative or that 2x -3? so then thats 3/2 right?

anonymous · Answer

is t squared -3x-4 already the derivative? because i have mult choice answers and they are -7, -4, -1, 1, and 4