Question

A number of discs, each of momentum M kg m/s are striking a wall at the rate of n discs per minute. The force associated with these discs, in newtons, would be

Answer 1

momentum divided by time equals to force
the force=\[(M \times n)\]\[\div60\]

Answer 2

\[(M \times n)\div60\]

Answer 3

Right. Impulse = integral of Force over time = change in momentum
==> Force = (change in impulse)/( time) = (change of momentum) / (time)

Answer 4

oh wait it should be 2(Mxn)÷60 because the change in momentum should be 2M

Answer 5

Assuming it is elastic collision