A number of discs, each of momentum M kg m/s are striking a wall at the rate of n discs per minute. The force associated with these discs, in newtons, would be

Question

anonymous · Answer

momentum divided by time equals to force
the force=$$(M \times n)$$$$\div60$$

anonymous · Answer

$$(M \times n)\div60$$

jamesj · Answer

Right.  Impulse = integral of Force over time = change in momentum
==> Force = (change in impulse)/( time) = (change of momentum) / (time)

anonymous · Answer

oh wait it should be 2(Mxn)÷60 because the change in momentum should be 2M

anonymous · Answer

Assuming it is elastic collision