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Mathematics 7 Online
OpenStudy (anonymous):

in a certain region, the ages of licensed drivers is normally distributed with a mean of 44.5 years and a standard deviation of 9,1 years. Find the percentage that a randomly selected driver is younger than 25

OpenStudy (anonymous):

How to make 44.5 years and a standard deviation of 9,1 years into a standard normal? Do you have the formula?

OpenStudy (anonymous):

I dont know the formula...that is the problem. I have all these notes and i am so lost..

OpenStudy (anonymous):

Okay z = (x - mean)/ standard deviation I would start a new page of notes and keep this formula in a safe place.

OpenStudy (anonymous):

i tried that but that doesnt give me the right answer

OpenStudy (anonymous):

the answers are a 1.6% b 2.7% c 4.9% d 88.4%

OpenStudy (anonymous):

z = (25 - 44.5)/9 = -2.17 What do we do next?

OpenStudy (anonymous):

I have no idea :/

OpenStudy (anonymous):

Hmm. Are you okay with the formula? Did you get the same answer?

OpenStudy (anonymous):

yes, well i got - 2.14 i did 25-44.5 seperate then divided by 9.1

OpenStudy (anonymous):

Ohh, 9,1 meant 9.1?

OpenStudy (anonymous):

Do you have your z-table with all of those numbers in it?

OpenStudy (anonymous):

i never got a z table..i dont even know what that means

OpenStudy (anonymous):

i was absent 3 days i had to go to Ohio for an emergency

OpenStudy (anonymous):

Ohh, hope everything is okay. Google has a z-table if you missed school on that day https://www.google.com/search?q=z-table&hl=en&prmd=imvns&tbm=isch&tbo=u&source=univ&sa=X&ei=PCoCT9zSPKaciQLswMDQDg&sqi=2&ved=0CCkQsAQ&biw=1024&bih=613

OpenStudy (anonymous):

thank you..i dont understand it at all..but thanks anyways

OpenStudy (anonymous):

did you look at one of the charts? We need to find 2.14 using the outside of the chart?

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