Solve the permutation. 11 P 9 / 11 P 8
simplify
do you know what is permutation?
Yeah, I think. like for the 11 P 9, you would do: 11*10*9 right?
no
\[11\text{ P }9=\frac{11!}{2!}\] yes?
Yeah, I understand so far.
isn't that factorial?
yes. and also \[11\text{ P }8=\frac{11!}{3!}\] so when you divide, invert and multiply
11! = 11*10*9*8*7*6*5*4*3*2*1?
\[nPk=\frac{n!}{(n-k)!}\] that's formula for permutations
so you get a huge cancellation are are left with very little
thomas.a wrote the formula, i used the numbers. you are dividing one by the other. invert and multiply cancel the 11! and then see what you get
11! / 2! = 19958400?
i know that you did but i wrote in general form and it's explained how you got denominator
you should do like satellite advised
k
whenever you are dealing with factorials, cancel first, multiply last
Cancel 11!?
yes. there is one in the numerator and one in the denominator. out they go
okay so 11! is no longer there. Just 2!, and then 3!?
\[\frac{11!}{2!}\div \frac{11!}{3!}=\frac{11!}{2!}\times \frac{3!}{11!}\]
and just to confirm, 11! would mean you do this math?: 11*10*9*8*7*6*5*4*3*2*1
that is the meaning of 11! yes
but in this case you do no such thing. just cancel them to get \[\frac{3!}{2!}=\frac{3\times 2}{2}=3\]
So all you do to find this answer is find 11! * 3!, and 2! * 11, then divide the two large numbers?
cancel cancel cancel. \[\frac{11!}{11!}=1\]
okay i got it now. thanks.
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