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Optimization: A rectangle is bounded by the x-axis and the semicircle y= (25-x^2)^1/2 . what length and width should the rectangle have so its area is a maximum?
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\[y=\sqrt{25-x^2}\] heres a better view of the equation
see it from here|dw:1325549133517:dw|
If you draw such a rectangle such that the base is from -x to x and the height is y, the area is A = 2xy Now substitute for y and you have a function A = f(x). Use calculus now to find the maximum of f(x)
|dw:1325549207229:dw|
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