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what's the derivative of tan^-1 (lnx)
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1/[x*{1+(lnx)^2}]
what happened to the tan function?
thats tan inverse, isnt it?
I believe so. I read a negative sign on a trig function is an inverse and not a fractional exponent
It is inverse otherwise the power should be after the ln(x).
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hmm.. derivative of tan inverse x is 1/(1+x^2) so, here replace x with ln x and apply chain rule.
Ok. I keep forgetting the how the chain rule works. Can you please explain it.
at first, differenciate the tan inverse function then differenciate the ln x, thats 1/x multiply both
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