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Mathematics 7 Online
OpenStudy (anonymous):

Simplify

OpenStudy (anonymous):

jhonyy9 (jhonyy9):

n2 +3n +2 = (n+1)(n+2)

OpenStudy (anonymous):

so its

jhonyy9 (jhonyy9):

when you need divide two fractions you can multiply first by second inversed

jhonyy9 (jhonyy9):

lisa what is this ?

OpenStudy (anonymous):

idk..

OpenStudy (anonymous):

i think the answer is 1

jhonyy9 (jhonyy9):

after you factorized these fractions and simplify i think that you are right with 1

jhonyy9 (jhonyy9):

ok ?

jhonyy9 (jhonyy9):

lisa is it ok ?

OpenStudy (anonymous):

yes :)

OpenStudy (phi):

\[\frac{n^2+3n+2}{2}\div\frac{(n+1)}{2(n+2)}= \frac{n^2+3n+2}{2} \cdot \frac{2(n+2)}{(n+1)}\] notice that you flip the second fraction to get rid of the division. after factoring the top of the first fraction you get \[\frac{\cancel{(n+1)}(n+2)}{\cancel{2}}\cdot\frac{\cancel{2}(n+2)}{\cancel{(n+1)}}=(n+2)^2\]

jhonyy9 (jhonyy9):

(n+2) squared is right sure

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