Question

See attachment.

Answer 1

look at the graph b) :D

Answer 2

It is a minimum because the parabola is concave upward and so it has a low point.

Answer 3

You can tell it has a low point because the coefficient of the x-squared term is positive.

Answer 4

oh dear, thought we cleared this up

\[\frac{1}{5}(x+5)^2\geq 0\] so
\[\frac{1}{5}(x+5)^2+3\geq3\] and therefore 3 is the MINIMUM value

Answer 5

Thx