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Mathematics 17 Online
OpenStudy (anonymous):

See attachment.

OpenStudy (anonymous):

OpenStudy (across):

\[\frac{t^2-4}{(t+2)^2}.\]Take a look at the numerator. Do you see any way we could "factor" it?

OpenStudy (anonymous):

no

OpenStudy (across):

Would you agree that \(t^2-4=(t+2)(t-2)\) ?\[\]

OpenStudy (anonymous):

yes

OpenStudy (across):

Then we're now left with\[\frac{(t+2)(t-2)}{(t+2)^2}.\]Can we simplify this any further?

OpenStudy (anonymous):

(t+2) (t-2)/ (t+2)(t+2).... this is the original equation factor. so u just cancel out like terms and ur left with... t-2/ t+2

OpenStudy (across):

sigh... Effectively enough,\[\frac{(t+2)(t-2)}{(t+2)^2}=\frac{(t+2)(t-2)}{(t+2)(t+2)}=\frac{(t-2)}{(t+2)}.\]

OpenStudy (anonymous):

so is that the answer. (t-2)/(t+2)

OpenStudy (across):

That's correct...

OpenStudy (anonymous):

yep

OpenStudy (anonymous):

THX

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