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integral x/((1-x^2)^(1/2)) dx
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\[\int\limits \frac{x}{\sqrt{1-x^2}}dx ?\]
Make the substitution: \[\zeta=1-x^2 \implies d \zeta=-2x dx \implies \frac{-1}{2} d \zeta =x dx\] Replacing this the integral becomes: \[\frac{-1}{2}\int\limits \frac{d \zeta}{\sqrt{\zeta}}=\frac{-1}{2}\int\limits \zeta^{\frac{-1}{2}}d \zeta=-\zeta^{\frac{1}{2}}+C=-\sqrt{1-x^2}+C\]
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