A polynomial P(x) is divided by x-2. The quotient is 2x^2+x-2 and the remainder is -1. Find P(x). PLEASE show steps!!!
multiply the divisor for the quotient and add remainder, so (x-2)*(2x^2+x-2)-1 is the solution
So I have to distribute the (x-2) to the quotient? And at the end, subtract 1?
yup
Awesome, just got the answer. Thanks a lot. (my grade depended on that one lol)
hear me, if you divive, you have a quotient right, and the remainder is the part that you cannot divide, so if you remoultiply the quotient and readd the remainder you'll get the initial number, or polynomial or everything ;)
Thanks. Ill definitely keep that in mind.
you're welcome, I hope this help :D
...by the way the cool way to divide a polynomial by something of the form (x-a) is through what is called synthetic division. way simpler than polynomial division often. http://www.purplemath.com/modules/synthdiv.htm http://www.youtube.com/watch?v=bZoMz1Cy1T4
I know it could be done through synthetic division but it was confusing since it gave me the divisor, quotient, and remainder. I assumed that I had to work backwards.
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