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Mathematics 7 Online
OpenStudy (anonymous):

differentiat log(logx)

OpenStudy (anonymous):

1/(x log x)

OpenStudy (anonymous):

Use chain rule.

OpenStudy (anonymous):

oh i got it thanks

OpenStudy (anonymous):

how do you do this question log x3

OpenStudy (anonymous):

what is log x3?

OpenStudy (anonymous):

\[\log _{x} 3\]

OpenStudy (anonymous):

when you differentiate it?

OpenStudy (anonymous):

that is same as (Log 3 / log x) so it will be log3/(x(log x)^2)

OpenStudy (anonymous):

why is it the same as (Log 3 / log x)

OpenStudy (turingtest):

change of base\[\log_ax\to\log_bx\]is done by\[\frac{\log_bx}{\log_ab}\]

OpenStudy (turingtest):

for your formula a=x and b=whatever you want it to I guess. Natural log is a good choice.

OpenStudy (anonymous):

differential of log x to base 'e' is just 1/x but differential of log x to base y is 1/(x log y). By a property of log, log x base y = (log x)/ log y here both logs on the rhs can be to any same base i have taken that base as e and then applied chain rule.

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